Monthly Archives: February 2013

Why You Need a Road Ramp with Your Next Pump Hire

Road RampDuring routine utilities maintenance, it is sometimes necessary to pump water across a road. This normally involves removal of the road surface in order to lay a temporary hose, and reinstatement of the road surface upon works completion. Not only is this a costly process, but disruption to the flow of traffic is unavoidable.

To eliminate this unnecessary cost, Maris Pumps Ltd has developed the Road Ramp, a unique, patented pipe ramp which allows water to be pumped across a road whilst maintaining traffic flow and rendering the job of digging up the road completely redundant. Simply connect the Road Ramp in-line with your hose using the integrated Bauer couplings, and start the pump.

Key to the Road Ramp‘s strength and durability is its triangular profile. The flat centre-section of traditional pipe ramp road crossings (which have a tendency to collapse under use causing leaks) has been removed at the design stage. In fact, we’ve load-tested the Road Ramp up to 70 tonnes – more than enough for a fully laden fire engine or articulated lorry.

Our unique, registered design means we’re the only company able to offer a road crossing ramp with a low apex height of just 75 mm – that’s 25% less than the maximum permitted height for a speed bump!

Road Ramp

The flat, low design of the ramp enables traffic to pass virtually undisrupted (without the risk of bottoming-out) while you pump up to 550 m³/hour through the free-flowing hose section. The design also eliminates the need for a box junction, ensuring that the Road Ramp doesn’t “rag up” even on heavy sewage jobs.

It is fitted with 6″ Bauer compatible couplings as standard and has lifting eyes for easy on-site handling.

The Road Ramp saves time, money and effort, allowing you to get your work completed quicker.

How to understand a Pump Flow Curve

When considering a new pump, you will invariably come across a graph which shows the pump’s performance characteristics. This will normally be a curve (or straight line) of flow rate against head.

Defining Pump Head

Head, usually given in units of meters or feet, is really just a measure of the pressure a pump can produce. It tells you the maximum vertical height to which a pump can deliver water (and not the horizontal distance or maximum hose length it will pump).

Take a look at the curve below for one of our most popular submersible pumps, the RSD-400 Puddle Pump.
RSD-400 Submersible Puddle Pump Flow Curve
You can see that the maximum delivery head for this pump is 11m when the delivery volume (or flow rate) is 0 (zero) l/m. What does this mean? Quite simply that the pump can lift water to a vertical height of 11m, but will not deliver any flow – the weight of the water will equal the amount of “push” the pump can produce (or more correctly the pressure it can generate).

The pump will need to generate 1 psi of pressure to “push” a column of water vertically up by 2.307 ft, therefore our RSD-400 will produce maximum pressure of:

11 m = 36.01 ft

36.01 ft / 2.307 ft = 15.6 psi

So, what if the height you’re pumping to is less than the maximum delivery head? The “left-over” pressure will be used to actually pump the water. For instance, at just under 7 m head, the pump will deliver approximately 100 l/m of water and with zero head the pump will deliver its maximum flow rate, in this case 180 l/m.

Another way to visualise this is to imagine a pump which has a pressure gauge and valve connected on the outlet. With the pump running and the valve closed, the pressure gauge will display the maximum pressure (or head) it can produce. If you slowly start to open the valve and let the water flow out, the pressure will drop until it reads zero when the valve is fully open (maximum flow rate).

This however, doesn’t tell the whole story – you also have to factor in the friction losses in the delivery hose. Using our on-line friction loss calculator, you can determine the pressure (or head) loss for flow through a length of hose.

Let’s consider a real-world example for a submersible “puddle sucker” pump

A cellar measuring 4 m x  4 m has been flooded to a depth of 300 mm. Using the RSD-400 and a 10 m length of 32 mm layflat hose we shall pump the water out through the coal shoot (a total height of 3 m).

RSD-400 Submersible Puddle Pump Pumping Out Flooded Cellar

Referring back to the flow curve, you can see that a 3 m head would give us roughly 150 l/m of flow at the pump outlet. Using our pressure drop calculator, we can determine that the friction losses in the layflat hose would be equivalent to an extra 2.8 m head, making our total head 5.8 m. Again, referring back to the flow curve this gives approximately 112 l/m of flow.

The volume of water in the cellar is as follows:

4m x 4m x 0.3 m = 4.8 m³ = 4800 litres

Therefore, assuming there is no further ingress of water and at a flow rate of 112 l/m, our pump would take 43 minutes to drain the cellar.

How Maximum Suction Lift Changes with Altitude and Atmospheric Pressure for an End-Suction Pump

MountainThe maximum vertical distance an end-suction pump can “suck” water is determined by two parameters: the altitude at which the pump is situated (and therefore the atmospheric pressure) and the design of the pump.

Since end-suction pumps, don’t actually suck the water up the hose (they create a vacuum and rely on atmospheric pressure to “push” the water up), the maximum suction lift is determined by the pump’s altitude. Generally speaking, the closer to sea level the more suction lift is available and the easier the pump is to prime.

The table below shows the theoretical limit and a more realistic maximum for maximum suction lift.

Altitude (m) Atmospheric Pressure (kg/cm2) Theoretical Max. Suction Lift (m) Realistic Max. Suction Lift (m)
0 (Sea Level) 1.03 10.33 7.52
100 1.02 10.21 7.40
200 1.01 10.09 7.28
300 1.00 9.97 7.16
400 0.99 9.85 7.04
500 0.97 9.73 6.92
600 0.96 9.62 6.81
636 (Kinder Scout) 0.96 9.58 6.76
700 0.95 9.50 6.69
800 0.94 9.39 6.58
900 0.93 9.28 6.46
978 (Scafell Pike) 0.92 9.19 6.38
1000 0.92 9.17 6.35
1344 (Ben Nevis) 0.88 8.79 5.98
2000 0.81 8.11 5.29
3000 0.71 7.15 4.34
4000 0.63 6.29 3.47
4810 (Mont Blanc) 0.57 5.65 2.84
5000 0.55 5.51 2.70

How does an end-suction pump work?

Or, more commonly, “How far up will a pump suck?”

A common question asked on our hire desk is “how far up will a pump suck?”. The simple answer is, at least in theoretical terms, 10.34 m. However, as simple answers go, it’s a little bit wrong (or at least not quite right). The reason is that the 10.34 m limit assumes perfect conditions: that you’re pumping at sea level, that the pump produces a perfect vacuum, that the water is cold and that there are no friction losses in the suction hose. In reality, the actual limit is 7 or 8 m.

Why a theoretical 10.34 m limit on suction lift?

Part of realising of how this limit arises from comes from understanding the fundamentals of how an end-suction pump operates. Firstly, pumps don’t suck – they produce a vacuum and rely on atmospheric pressure (or more simply, the weight of the atmosphere) to “push” the water up the suction hose. The water flows from an area of high pressure to an area of low pressure – a low pressure region (i.e. a vacuum) is created inside the pump and the pressure differential raises or lifts the water up the suction hose.

The 10.34 m limit is the point where the weight of the atmosphere “pushing” the water up the hose equals the weight of water in the hose.

Why a 7 or 8 m real-world limit on suction lift?

Since real-world pumps aren’t capable of producing a perfect vacuum, a more realistic limit of 7 or 8 m can be calculated. This is the point where the weight of water in the hose equals the force from the difference between atmospheric pressure and the less-than-perfect vacuum the pump is producing.

Maximum Suction Lift Explained in Pictures

Confused yet? Take a look at the diagram below – Column A is a hollow tube with a cross-sectional area of 1 cm² (why 1 cm²? It makes the following calculations a bit easier) representing the suction hose. If one end of the tube is open to the atmosphere (analogous to the pump being switched off), and the other end is submerged under water, then there will be no pressure differential and so no force applies. Therefore, the water isn’t “pushed” up the tube.

Maximum Suction Lift for An End-Suction Pump

Column B is also a hollow tube of cross-sectional area of  1 cm². If the top end of the tube is sealed and subjected to a perfect vacuum (analogous to a theoretical super-pump) and the other end is submerged underwater, then a pressure differential will exist and the weight of the atmosphere will “push” the water up the tube. The height the water rises to, and therefore the maximum possible suction lift, can be calculated as follows:

Atmospheric pressure at sea level = 14.7 psi = 1.034 kg/cm² (effectively the weight of the atmosphere acting on every square centimetre of the water’s surface).

Vacuum Pressure inside sealed tube = 0 psi = 0 kg/cm² (a perfect vacuum)

Weight of 1 cm³ of water = 0.001 kg

(Atmospheric Pressure – Vacuum Pressure) / Weight of Water

(1.034 kg/cm² – 0 kg/cm²) / 0.001 kg = 1034 cm = 10.34 m

So this gives a value of 10.34 m for the maximum possible suction lift under perfect conditions. In reality this will never be achieved – even the most efficient pumps aren’t capable of producing a perfect vacuum and then you still need to factor in friction losses in the suction hose, water temperature (the warmer the water, the less the suction lift) and even the altitude (as you move up from sea level the atmospheric pressure decreases, effectively reducing the amount of “push” available).

So, what’s a more realistic figure? Let’s ignore water temperature, friction losses and altitude and concentrate only the how much vacuum a real-word pump can produce. Taking a look at the diagram, Column C is also a hollow tube of cross-sectional area of 1 cm² with a sealed top end subjected to a partial vacuum with the other end submerged underwater. Now since the tube is only subjected to a partial vacuum (just like a real world pump produces), the pressure differential is less, meaning that the water is raised or lifted up the tube to a reduced height.

Performing the same calculation again:

Atmospheric pressure at sea level = 14.7 psi = 1.034 kg/cm²

Partial Vacuum pressure inside tube = 4 psi = 0.2812 kg/cm² (a realistic amount how much of a vacuum a pump can produce)

(1.034 kg/cm² – 0.2812 kg/cm²) / 0.001 kg = 752 cm = 7.52 m

So, in this instance our real-world pump would have a maximum suction lift of 7.52 m, however you would still need to factor in other effects such as friction losses in the suction hose – making the actual value even lower.